Number Complement
Given a positive integer, output its complement number.
The complement strategy is to flip the bits of its binary representation.
1. The given integer is guaranteed to fit within the range of a 32-bit signed integer.
2. You could assume no leading zero bit in the integer’s binary representation.
Input: 5
Output: 2
Explanation: The binary representation of 5 is 101 (no leading zero bits), and its complement is 010.
So you need to output 2.
Input: 1
Output: 0
Explanation: The binary representation of 1 is 1 (no leading zero bits), and its complement is 0.
So you need to output 0.
Use ">>" and "&" operands to get each bit is 1 or 0.
Every time, do (input_num >> i) & 1.
If bit(i) is 0 zero, add (1 << i) to the result until input_number is zero
class Solution {
public int findComplement(int num) {
int result = 0;
int count = 0;
while (num > 0) {
if ((num & 1) == 0) {
result += 1 << count;
}
num >>= 1;
count++;
}
return result;
}
}
class Solution {
public:
int findComplement(int num) {
int count = 0;
int result = 0;
while (num > 0) {
if ((num & 1) == 0) {
result += 1 << count;
}
count++;
num >>= 1;
}
return result;
}
};
class Solution(object):
def findComplement(self, num):
"""
:type num: int
:rtype: int
"""
result = 0
count = 0
while num > 0:
if (num & 1) == 0:
result += 1 << count
num >>= 1
count += 1
return result
int findComplement(int num) {
int count = 0;
int result = 0;
while (num > 0) {
if ((num & 1) == 0) {
result += 1 << count;
}
count++;
num >>= 1;
}
return result;
}