Number of 1 Bits
LeetCode: Number of 1 Bits
Problem:
Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight).
For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should return 3.
- Analysis:
According to problems, the input is unsigned integer and want to get the Hamming weight.
Hamming weight is that the number of non-zero bit in a string.
- Code - Java:
public class Solution {
// you need to treat n as an unsigned value
public int hammingWeight(int n) {
int count = 0;
for (int i = 0; i < 32; i++) {
count += (n >>> i) & 1;
}
return count;
}
}
- Code - C++:
class Solution {
public:
int hammingWeight(uint32_t n) {
int count = 0;
while (n > 0) {
n &= (n - 1);
count++;
}
return count;
}
};
- Code - Python:
class Solution(object):
def hammingWeight(self, n):
"""
:type n: int
:rtype: int
"""
count = 0
for i in range(32):
count += (n >> i) & 1
return count
- Code - C:
int hammingWeight(uint32_t n) {
int count = 0;
while (n > 0) {
n &= (n - 1);
count++;
}
return count;
}